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Working with Channels

Go provides a mechanism called a channel that is used to share data between goroutines. When you execute a concurrent activity as a goroutine a resource or data needs to be shared between goroutines, channels act as a conduit(pipe) between the goroutines and provide a mechanism that guarantees a synchronous exchange.
Data type need to be specified at the time of declaration of a channel. We can share Values and pointers of built-in, named, struct, and reference types. Data are passed around on channels: only one goroutine has access to a data item at any given time: so data races cannot occur, by design.

There are two types of channels based on their behavior of data exchange: unbuffered channels and buffered channels. An unbuffered channel is used to perform synchronous communication between goroutines while a buffered channel is used for perform asynchronous communication. An unbuffered channel provides a guarantee that an exchange between two goroutines is performed at the instant the send and receive take place. A buffered channel has no such guarantee.

A channel is created by the make function, which specifies the chan keyword and a channel's element type.

Here is the code block that creates an unbuffered and buffered channel:

Unbuffered := make(chan int) // Unbuffered channel of integer type
buffered := make(chan int, 10)	// Buffered channel of integer type

The use of the built-in function make to create both an unbuffered and buffered channel. The first argument to make requires the keyword chan and then the type of data the channel will allow to be exchanged.

Here is the code block to send a value into a channel requires the use of the <- operator:

goroutine1 := make(chan string, 5) // Buffered channel of strings.
goroutine1 <- "Australia" // Send a string through the channel.

A goroutine1 channel of type string that contains a buffer of 5 values. Then we send the string "Australia" through the channel.

Here is the code block that receives values from a channel:

data := <-goroutine1 // Receive a string from the channel.

The <- operator is attached to the left side of the channel variable(goroutine1), to receive a value from a channel.

Unbuffered channels

In unbuffered channel there is no capacity to hold any value before it's received. In this type of channels both a sending and receiving goroutine to be ready at the same instant before any send or receive operation can complete. If the two goroutines aren't ready at the same instant, the channel makes the goroutine that performs its respective send or receive operation first wait. Synchronization is fundamental in the interaction between the send and receive on the channel. One can't happen without the other.

Buffered channels

In buffered channel there is a capacity to hold one or more values before they're received. In this types of channels don't force goroutines to be ready at the same instant to perform sends and receives. There are also different conditions for when a send or receive does block. A receive will block only if there's no value in the channel to receive. A send will block only if there's no available buffer to place the value being sent.

// Simple program to demonstrate use of Buffered Channel
package main
import (
var goRoutine sync.WaitGroup
func main(){
	// Create a buffered channel to manage the employee vs project load.
	projects := make(chan string,10)
	// Launch 5 goroutines to handle the projects.
	for i :=1; i <= 5; i++ {
		go employee(projects, i)
	for j :=1; j <= 10; j++ {
		projects <- fmt.Sprintf("Project :%d", j)
	// Close the channel so the goroutines will quit	
func employee(projects chan string, employee int) {
	defer goRoutine.Done()
	for {
		// Wait for project to be assigned.
		project, result := <-projects
		if result==false {
			// This means the channel is empty and closed.
			fmt.Printf("Employee : %d : Exit\n", employee)
		fmt.Printf("Employee : %d : Started   %s\n", employee, project)
		// Randomly wait to simulate work time.
		sleep := rand.Int63n(50)
		time.Sleep(time.Duration(sleep) * time.Millisecond)
		// Display time to wait
		fmt.Println("\nTime to sleep",sleep,"ms\n")
		// Display project completed by employee.
		fmt.Printf("Employee : %d : Completed %s\n", employee, project)

Every time you run this program the output for this program will be different this is because of the random nature of the program and the Go scheduler.
In above program, a buffered channel of type string is created with a capacity of 10. WaitGroup is given the count of 5, one for each goroutine. 10 strings are sent into the channel to simulate or replicate project for the goroutines. Once the last string is sent into the channel, the channel is going to be closed and the main function waits for all the project to be completed.